Exponentials and discounting
Grow money forward, discount it back, and spread a building cost into equal yearly payments
- Math toolbox
- 15 min guided · about 15 min practice
- No prerequisites
- Completed
Money over time, in six moves
- Growth compounds: $100 at 7% a year, interest left in, is $196.72 after 10 years and first passes $200 in year 11 ($210.49). Simple interest gives $170.00 after 10 years.
- Discounting runs it backwards: $100 paid in 10 years is worth $100 ÷ 1.07¹⁰ = $50.83 today, its present value.
- Far-off money feels the rate most: from 7% to 4%, $100 in 30 years rises from $13.14 to $30.83 today.
- $1 paid at the end of each year for 30 years is worth $17.29 today at 4%, not $30: the annuity factor.
- Spread the wind farm's building cost over 30 years: $1,712 ÷ 17.292 = $99.01 per kW a year. The capital recovery factor is 1 ÷ 17.292 = 0.05783.
- Add upkeep: $99.01 + $34.57 = $133.58 per kW a year; per MW, before rounding, 1,000 × $133.575 = $133,575. At 0% the factor is 1 ÷ 30 = 0.0333.
| When | $100 today grows at 7% to | $100 paid then is worth today, at 7% | … at 4% |
|---|---|---|---|
| Today | $100.00 | $100.00 | $100.00 |
| In 10 years | $196.72 | $50.83 | $67.56 |
| In 20 years | $386.97 | $25.84 | $45.64 |
| In 30 years | $761.23 | $13.14 | $30.83 |
| Rate (real) | CRF over 30 years | Repayment, $ per kW a year | Plus upkeep: yearly cost, $ per kW |
|---|---|---|---|
| 0% | 0.0333 | $57.07 | $91.64 |
| 4% | 0.0578 | $99.01 | $133.58 |
| 7% | 0.0806 | $137.96 | $172.53 |
With JavaScript on, you work through this step by step with sliders, a chart and your own answers.
- The wind farm's building cost, $1,712 per kW, and fixed upkeep, $34.57 per kW a year: EIA, AEO2026 assumptions, Table 3 (2025 dollars, April 2026), as in lessons 7, 12 and 13.
- 4% a year after inflation over a 30-year cost recovery period, as in lesson 7 and lesson 13: the 2025 ATB's period, and a round rate inside its range (NLR, September 2026).
- Each yearly payment falls at the end of its year, as the capital recovery factor assumes.
- $100 and 7% are illustrative, as in lesson 7's step 3. All dollars are real 2025 dollars, so every rate here is a real rate.
What you just did, as diagrams
- Compound growth
- Each year adds a percentage of what is there now, so the amount grows faster and faster: × (1 + r)t after t years.
- Present value
- What an amount paid t years from now is worth today: divide by (1 + r)t.
- Annuity factor
- What $1 at the end of each year for n years is worth today: the sum of the discounted dollars, 17.29 at 4% over 30 years.
- Capital recovery factor
- One over the annuity factor: the share of a building cost repaid each year, 0.0578 at 4% over 30 years.
- Yearly cost
- CRF × building cost + fixed upkeep: $99.01 + $34.57 = $133.58 per kW a year for the wind farm.
Go deeper · AnalystWhere the formula comes from, and real against nominal rates
- A stream is a geometric series: a sum in which each term is the one before times the same factor, here \(1 \div (1+r)\).
- Add it up. \(n\) yearly payments \(P\), each at the end of its year: \(\frac{P}{1+r} + \dots + \frac{P}{(1+r)^n} = P\,\frac{1-(1+r)^{-n}}{r}\). The fraction is the annuity factor: 17.29 at 4% over 30 years.
- Set it equal to the building cost \(C\) ($ per kW): \(P = \frac{r}{1-(1+r)^{-n}}\,C = \mathrm{CRF} \cdot C\), the yearly repayment before upkeep.
- Two ways to write it. Multiply top and bottom by \((1+r)^n\): \(\frac{r}{1-(1+r)^{-n}} = \frac{r(1+r)^n}{(1+r)^n - 1}\). Lesson 7 writes the first, lesson 13’s code the second.
- Exact doubling time. Solve \((1+r)^t = 2\) for \(t\): \(t = \ln 2 \div \ln(1+r)\), where \(\ln\) is the natural logarithm (a calculator’s ln key). At 7% that is 10.2 years; the rule of 70 says 10.
- Real against nominal. A nominal rate includes inflation; a real rate takes it out: \((1 + \text{nominal}) = (1 + \text{real})(1 + \text{inflation})\). Lesson 7’s illustrative blend, 7% nominal with 2.5% inflation, is 4.39% real.
- Do not mix them. Costs in today’s dollars go with a real rate; cash in the dollars of each future year goes with a nominal rate.
Go deeper · ModelerThe yearly cost inside a planning model (a preview)
- One year stands for the life. Lessons 12 and 13 minimise one year’s cost, \(1000 \sum_k (\mathrm{CRF}_k\, C_k + \mathrm{FOM}_k)\,K_k\) plus running costs, with \(K_k\) the MW built of plant \(k\).
- Units. \(C_k\) (building cost) and \(\mathrm{FOM}_k\) (fixed upkeep) are $ per kW and \(K_k\) is in MW, so the 1,000 (kW per MW) makes the units match: one MW of wind adds $133,575 a year.
- The assumption. Every year of the life looks like the modelled year, and each plant’s cost is recovered over \(n\) years at the same rate: 30 years for plants, 15 for lesson 13’s battery.
- Where next. A model that spans decades discounts each year’s cash instead, and credits plants that outlive its horizon (Modeler lesson M13); M11 puts a project’s full cash flow inside the optimization.
Check yourself
Myth or fact? “A plant paid off over 30 years costs 1/30 of its building cost each year.”
- Myth
- Fact
Answer
Myth, unless the rate is 0%. At 4% the yearly share is 0.0578, not 0.0333: lenders and owners are paid for the wait.
Myth or fact? “Doubling the discount rate halves what $100 paid in 30 years is worth today.”
- Myth
- Fact
Answer
Myth. From 3.5% to 7% it falls from $35.63 to $13.14, by 63%: the rate sits inside an exponent.
What is $100 paid in 20 years worth today, at 7% a year?
- $386.97
- $41.67
- $25.84
- $50.00
Answer
$25.84: 100 ÷ 1.07²⁰. $41.67 divides by 1 + 20 × 0.07 (simple interest); $386.97 grows the $100 forward instead.
Which is the capital recovery factor at 4% over 30 years?
- 0.0333
- 0.0400
- 0.0578
- 0.0806
Answer
0.0578. 0.0333 is 1 ÷ 30, the 0% case; 0.0400 pays the return but never the cost; 0.0806 is the factor at 7%.
Numbers, sources and what’s next
Numbers to remember
| Number | What it means | Source |
|---|---|---|
| 70 ÷ rate | Years to double at a steady rate in %, roughly: 10 years at 7%. | Rule of thumb; the exact time is in Go deeper |
| 0.0578 | The capital recovery factor at 4% over 30 years: the share of a building cost repaid each year. | This page, from the formula |
| $1,712 · $34.57 | The wind farm's building cost per kW and fixed upkeep per kW a year (2025 dollars). | EIA, AEO2026 assumptions, Table 3 (PDF) · April 2026 |
| 4% · 30 years | The real rate and cost recovery period of lessons 7, 12 and 13. | NLR, 2025 ATB · September 2026 (4%: a round value inside its range) |
| $133.58 | The wind farm's yearly cost per kW: $99.01 of repayment plus $34.57 of upkeep. | This page, from the formula |
Next
Sources and further reading
- EIA (2026). Assumptions to the Annual Energy Outlook 2026: Electricity Market Module (PDF). Table 3: building cost and upkeep.
- NLR (2026). 2025 Electricity Annual Technology Baseline: Equations and Variables (the capital recovery factor); Financial Cases and Methods (rates and the 30-year period).
- Where this is used: lesson 7 (present value, the capital recovery factor, LCOE), lesson 12 and lesson 13 (yearly costs in a planning model). Analyst lesson A1 builds on it, and so does Modeler lesson M11.
Spotted an error, or stuck? Write to hlli@ksu.edu. Corrections are made in place and dated here.
Text licensed CC BY 4.0, code MIT: teachers and students may reuse and adapt it, with credit to Honglin Li.